Kotlin arraylist9/14/2023 Under the covers, both mutableListOf() and arrayListOf() create an instance of ArrayList. Then you probably want to either use ArrayList directly, or use the arrayListOf factory function (an ArrayList-specific analogue to mutableListOf). On the other hand, maybe you spent a bunch of time thinking about your problem, and figured that ArrayList really is the best fit for your problem, and you don't want to risk getting moved to something sub-optimal. Go with mutableListOf if that sounds like your case. ![]() mutableListOf would then have you using that new list implementation transparently, and you'd get that better behaviour for free. ![]() Likelier than not, the Kotlin team would only make that change if they figure the new implementation works better for most use cases. Now, let's say that a future version of Kotlin changes mutableListOf to return a different type of list. In practice, in the current implementation of Kotlin compiling to the JVM, calling mutableListOf will produce an ArrayList, and there's no difference in behaviour: once the list is built, everything will behave the same. When you write, instead, val a = ArrayList(), you're saying "I specifically want an ArrayList". When you write val a = mutableListOf(), you're saying "I want a mutable list, and I don't particularly care about the implementation". ![]() * Sorting array of array list to get Biggest to smallest array List based of sizeĬollections.The only difference between the two is communicating your intent. It worked perfectly fine there but now I'm unable to achieve this in Koltin I'm getting an ERROR.Ĭonsider I've a class Foo() private var allHistoryList: ArrayList> = arrayListOf() I did the same thing in java using Collections. I have an ArrayList of ArrayList what I want to achieve is, to sort them in descending order (based on the Highest to lowest List size ) to get the largest first and onwards.
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